Yes, CH3OH (methanol) is a dipole. The molecule has a bent shape with a partial negative charge on the oxygen atom and partial positive charges on the hydrogen atoms. This unequal distribution of charge creates a dipole moment, making CH3OH a polar molecule. **

BF3 and CCl4 are nonpolar molecules because they have a symmetrical arrangement of their atoms, which results in a net dipole moment of zero. On the other hand, CH3OH is a polar molecule because it has a bent shape and the oxygen atom pulls the electron density towards itself, creating a net dipole moment. Therefore, BF3 and CCl4 are nonpolar, while CH3OH is a polar molecule. **

No, H3COH is not the same as CH3OH. H3COH refers to methoxy or methyl alcohol, while CH3OH refers to methanol. Methoxy or methyl alcohol has a methoxy group (CH3O) attached to a hydrogen atom, while methanol has a hydroxyl group (OH) attached to a carbon atom. Therefore, they are different chemical compounds with different structures and properties. **

H2O and CH3OH are both chemical compounds that contain hydrogen and oxygen atoms. They are both polar molecules due to the electronegativity difference between the atoms, which results in a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen or carbon atoms. Both H2O and CH3OH are capable of forming hydrogen bonds with other molecules, which gives them unique properties such as high boiling points and surface tension. However, CH3OH is a type of alcohol, while H2O is a simple molecule made of two hydrogen atoms and one oxygen atom. **

The chemical formula of methanol is CH3OH. This formula represents one carbon atom (C), four hydrogen atoms (H), and one oxygen atom (O) bonded together. The formula CH4O does not accurately represent the composition of methanol. **

Among the molecules N2, Cl2, H2O, and CH3OH, the molecule with the lowest boiling point is N2 (nitrogen gas). This is because N2 is a nonpolar molecule with only London dispersion forces between its molecules, which are weaker compared to the dipole-dipole and hydrogen bonding present in the other molecules. Therefore, N2 requires less energy to overcome these intermolecular forces and transition from a liquid to a gas, resulting in a lower boiling point. **

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